Chad wants to build a dog kennel with 64ft of fence.?

.

He wants to put two dividers of fence in it. Find the largest total area for the dog kennel.

Thanks for all of your help!

Other Dog Fence Sites Online




3 Responses to “Chad wants to build a dog kennel with 64ft of fence.?”

  1. Angel Rosewood says:

    The kennel is a square so thats 4 pieces the same size. The dividers need to be the same length. Thats 6 pieces. 64 divided by 6 is 10 ft and 8 inches.That’s what each piece has to be. Multiply that by 2 and you get the area of 101 ft and 4 inches.

    10 ft and 8 inches is the maximum length of each piece of fence and dividers with only 64 ft of fence.

  2. Jim says:

    W = width
    L = length

    4W + 2L = 64

    L = [64 – 4W]/2

    L = 32 – 2W

    A = LW = 32W – 2W^2

    dA/dW = 32 – 4W = 0

    4W = 32

    W = 8, L = 8

    A = 64

  3. Keith says:

    Are the dividers parallel to make 3 areas
    or perpendicular to make 4 areas?

    assuming they are parallel for 3 runs.

    Let x = length
    Let y = width of one of three areas … 3y = total width

    Fencing used
    4x + 6y = 64 ft.
    y = (64 – 4x) / 6

    Total area
    x * 3y
    . . . sub for y
    A = x * 3 * (64 – 4x) / 6
    A = 32x – 2x^2

    . . . A is maximized when A’ = 0

    A’ = 32 – 4x
    32 – 4x = 0
    x = 32 / 4 = 8

    y = (64 – 4*8) / 6 = 16 / 3
    3y = 16

    Total area = 8 * 16 = 128 square feet

Copyright © 2011 Fences for Dogs. All Rights Reserved. About Us | Contact Us | Terms of Use | Privacy Policy | Site Map